Apparent power S = VI,Real power, P = VI cos ϕ,Reactive power, Q = VI sin ϕ
RC
SERIES CIRCUIT
Fig
1.33 shows the RC series circuit
Where
R
- Resistance in Ω
C
- Capacitance in F
I
- Current flowing through the RC circuit
V
- Input voltage
VR
- Voltage drop across resistance = IR
VC
- Voltage drop across capacitance = I Xc
Phasor
diagram for RC series circuit is shown in fig 1.34
Impedance
Phase angle ϕ = tan-1 XC/R
Power
factor = cos ϕ = R/Z
Apparent
power S = VI
Real
power, P = VI cos ϕ
Reactive
power, Q = VI sin ϕ
Example: 16
A series RC circuit has R = 100 2
and XC = 200. The supply voltage is 50 V. Find the apparent power,
real power and reactive power for the circuit shown in figure.
R
= 100 Ω, X = 200 Ω
Impedance
=
223.6 Ω
Power
factor, cos ϕ =
=
0.447
Current
I = V/Z = 50/223.6 = 0.223 A
Apparent
power, S = VI
=
50 x 0.223
=
11.15 VA
Real
power, P = VI cos ϕ
=
50 × 0.223 × 0.447
=
4.984 W
Reactive
power, Q = VI sin ϕ
=
50 x 0.223 × 0.894
=
9.96 VAR
Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits : Tag: : Basic Circuit diagram, Phasor diagram, Formula with Solved Example Problems | Electrical Circuits - RC Series Circuit
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