Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits
Grouping of Capacitors
with Solved Example Problems | Electrical Circuits
Two capacitances C1 and C2 are connected in series across voltage V. Let C is the equivalent capacitance and current is I.
GROUPING
OF CAPACITORS
Two
capacitances C1 and C2 are connected in series across
voltage V. Let C is the equivalent capacitance and current is I as shown in fig
1.20
Here the applied voltage is the summation of the individual voltage drops across C1 and C2.
V
= drop across C1 + drop across C2
If
the capacitances C1 and C2 are connected in parallel i1
and i2 are branch currents, the total current I as shown in fig
1.21.
Total
current i = i1 + i2
C=C1
+ C2
Example: 14
Two capacitances of 2μF are
connected in series. What is the equivalent capacitance?
Example: 15
Find the equivalent capacitance
across A - B as shown in fig.
The
equivalent capacitance of C2 and C3 is
Ceq1
is parallel with the capacitance C1
Ceq2
= C1 +Ceql
=
2 + 1 = 3μF
Ceq2
and C4 are connected in series.
Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits : Tag: : with Solved Example Problems | Electrical Circuits - Grouping of Capacitors
Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits
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