Consider the pure capacitor connected across a sinusoidal supply. The voltage and current are out of phase. The current leads the voltage by 90°.
PHASE
RELATION IN PURE CAPACITOR
Consider the pure capacitor connected across a sinusoidal supply. The voltage and current are out of phase. The current leads the voltage by 90°.
V(t)
= Vm sin (ωt - 90°)
Impedance
Z =
where
XC
- capacitive reactance
Example: 11
In an AC circuit, the applied
voltage is given by V = 200 sin 314 t and the expression for the leading
current is given by i = 10 cos 314 t. Find the circuit constant and the power
factor of the circuit. Draw the phasor diagram.
V
= 200 sin 314 t
i
= 10 cos 314 t
i
= 10sin (314t+π/2)
Vm
= 200, Im = 10
ω = 314
C
= 159μf
Power
factor = cos ϕ = cos π/2 = 0
Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits : Tag: : Circuit, Waveform, Formula with Solved Example Problems | Electrical AC Circuits - Phase Relation in Pure Capacitor
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