Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits
Phase Relation in a Pure Inductor
Circuit, Waveform, Formula with Solved Example Problems | Electrical AC Circuits
When a sinusoidal voltage is applied across a inductor, a certain amount of sine wave current passes through it.
PHASE
RELATION IN A PURE INDUCTOR
When
a sinusoidal voltage is applied across a inductor, a certain amount of sine
wave current passes through it. In a pure inductor the voltage and current are
out of phase. The current lags behind the voltage by 90°.
where
Vm
= ωLIm
=
XL Im
Impedance
Z = 
Z
= j XL
Where
XL - Inductive reactance
Example : 10
An inductive coil has negligible
resistance an inductance of 0.1H. It is connected across a 220V, 50Hz supply.
Find the current and power. Also write the expression for instantaneous applied
voltage and current.
L
= 0.1 H
V
= Vrms = 220V
f
= 50 Hz
Current
I = 
=
7A
Average
power = VI cos ϕ
=
VI cos 90°
=
0
Instantaneous
voltage
V
= Vm sin ωt
= √2×220
=
311 V
ω
= 2πf
=
2×π×50
=
314 r/s
V
= 311 sin 314 t
Instantaneous
current
i
= Im sin (ωt - π/2)
=
9.9 A
i
= 9.9 sin (314t - π/2)
Basic Electrical and Electronics Engineering: Unit I: Electrical Circuits : Tag: : Circuit, Waveform, Formula with Solved Example Problems | Electrical AC Circuits - Phase Relation in a Pure Inductor
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