It is built around a four - diode bridge configuration. This design is called as full wave bridge. It is most popular of full wave rectifier design.
FULL WAVE BRIDGE:
It is built around a four - diode bridge configuration. This design is called as full wave bridge. It is most popular of full wave rectifier design.
A bridge rectifier makes use of four diode in a bridge arrangement to achieve full-wave rectification. It is a widely used configuration, both with individual diodes wired and with single component bridges where the diode bridge is wired internally.
It is most widely used rectifier. In the positive half cycle, D1 and D4 is forward biased and D2 and D3 are reverse biased. In the negative half cycle D2 and D3 are forward bias and D1 and D4 are reverse bias. The output voltage waveform is same but the advantage is that PIV rating of diodes are Vm and only single secondary transformer for Vm voltage is required. The main disadvantage is that it requires four diodes. When now d.c. voltage is required then secondary voltage is low and diode drop (1.4 V) becomes significant. The Xƒ1, required is of high rating (> 1.4 V).
For low d.c output we use center tap rectifier because only one diode drop is there.
Current directions for the full wave bridge rectifier for the positive and negative. half cycles of AC source waveform.
Regardless of the polarity of the input, the current flows in the same direction through the load (i.e) the negative half cycle of source is positive half cycle at the load. The current flow is through two diodes in series for both polarities. Thus two diode drops of the source voltage are lost (0.7 × 2 = 1.4 V for Si) in the diodes. This is a disadvantage compared with a full wave center, tap design. This disadvantage is only a problem in very low voltage power supplies.
• High efficiency.
• Low ripple factor.
• High TUF.
• Complicated circuit
• High cost
For half wave rectifier,
Idc = 1/π . Im = 0.318 Im
Irms = ½ .Irms = 0.5Im
Vdc = 1/π . Vm = 0.318 Vm
Vrms = ½ Vm = 0.5 Vm
For a full wave rectifier
Idc = 2/π . Im = 0.637 Im
Irms = 1/√2 .Im = 0.707Im
Vdc = 2/π . Vm = 0.637 Vm
Vrms = 1/√2 .Vm = 0.5 Vm
Basic Electrical and Electronics Engineering: Unit III: Analog Electronics : Tag: : Circuit diagram, Operation, Merits, Demerits - Full Wave Bridge
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